Andrei Merinov vs Jean Francois Bachelot — India Masters 3 Qualifying Round
India Masters 3 · ITF · Qualifying Round
2 — 1
Sets
Saturday, 28 December 1996 ·
clay
Merinov A.7-5 5-7 7-6
Francois Bachelot J.
Merinov A.
7572
Francois Bachelot J.
5761
Andrei Merinov defeated Jean Francois Bachelot 7-5 5-7 7-6 in the India Masters 3 qualifying round on clay. The upset overturned the form book — Jean Francois Bachelot came in leading the head-to-head 1–0. Andrei Merinov claimed a first win over Jean Francois Bachelot in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Andrei Merinov edged Jean Francois Bachelot in three tight sets (7–5 5–7 7–6).
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1996-12-28 | India Masters 1 | R32 | clay | Jean Francois Bachelot | 6-3 4-6 6-4 |
Statistics
This season1st serve in·Slight edge
64%
54%
1st serve points won·Even
61%
63%
2nd serve points won·Even
43%
47%
Service points won·Even
54%
56%
Return points won·Even
36%
37%
Break points saved·Slight edge
48%
57%
Aces / match·Clear edge
1.0
3.5
Double faults / match·Even
3.6
3.8
Averages over each player's completed matches in the selected window (9 vs 11). ATP, WTA & Challenger.