Jean Francois Bachelot vs Andrei Merinov — India Masters 1 Round of 32
India Masters 1 · ITF · Round of 32
2 — 1
Sets
Saturday, 28 December 1996 ·
clay
Francois Bachelot J.6-3 4-6 6-4
Merinov A.
Francois Bachelot J.
6462
Merinov A.
3641
Jean Francois Bachelot defeated Andrei Merinov 6-3 4-6 6-4 in the India Masters 1 round of 32 on clay. The upset overturned the form book — Andrei Merinov came in leading the head-to-head 1–0. Jean Francois Bachelot claimed a first win over Andrei Merinov in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Jean Francois Bachelot closed it out in three sets, 6–3 4–6 6–4.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1996-12-28 | India Masters 3 | QF | clay | Andrei Merinov | 7-5 5-7 7-6 |
Statistics
This season1st serve in·Slight edge
54%
64%
1st serve points won·Even
63%
61%
2nd serve points won·Even
47%
43%
Service points won·Even
56%
54%
Return points won·Even
37%
36%
Break points saved·Slight edge
57%
48%
Aces / match·Clear edge
3.5
1.0
Double faults / match·Even
3.8
3.6
Averages over each player's completed matches in the selected window (11 vs 9). ATP, WTA & Challenger.