Francesca Lubiani vs Tatiana Panova — Roland Garros Q64
Roland Garros · WTA · Q64
2 — 0
Sets
Monday, 27 May 1996 ·
clay
Lubiani F.6-1 6-4
Panova T.
Lubiani F.
662
Panova T.
140
Francesca Lubiani defeated Tatiana Panova 6-1 6-4 in the Roland Garros q64 on clay. Francesca Lubiani extended the head-to-head to 2–1.
Key context
- Match story: Francesca Lubiani dropped just 5 games past Tatiana Panova.
Head to head
1–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1998-01-19 | Australian Open | R128 | hard | Tatiana Panova | 6-4 6-4 |
| 1997-08-11 | Canadian Open | R64 | hard | Francesca Lubiani | 6-2 7-6 |
Statistics
This season1st serve in·
—
61%
1st serve points won·
—
54%
2nd serve points won·
—
40%
Service points won·
—
49%
Return points won·
—
40%
Break points saved·
—
51%
Aces / match·
—
0.8
Double faults / match·
—
5.9
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.
Conditions
Court speed
Slowlow bounce, long rallies
SlowFast