Hernan Gumy vs David Wheaton — Australian Open Round of 64
Australian Open · ATP · Round of 64
3 — 1
Sets
Monday, 15 January 1996 ·
hard
Gumy H.6-3 6-7 6-4 7-5
Wheaton D.
Gumy H.
663673
Wheaton D.
377451
Hernan Gumy defeated David Wheaton 6-3 6-7 6-4 7-5 in the Australian Open round of 64 on hard. The result followed the form book — Hernan Gumy came in leading the head-to-head 1–0. Hernan Gumy extended the head-to-head to 2–0.
Key context
- Match story: Hernan Gumy closed it out in four sets, 6–3 6–7 6–4 7–5.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1995-05-15 | Coral Springs | R16 | clay | Hernan Gumy | 6-3 7-6(5) |
Statistics
This season1st serve in·Even
63%
60%
1st serve points won·Even
67%
71%
2nd serve points won·Even
47%
47%
Service points won·Even
59%
61%
Return points won·Even
39%
37%
Break points saved·Slight edge
56%
63%
Aces / match·Dominant
2.7
6.1
Double faults / match·Clear edge
3.7
5.0
Averages over each player's completed matches in the selected window (124 vs 39). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast