Chanda Rubin vs Helena Sukova — US Open Round of 64
US Open · WTA · Round of 64
2 — 0
Sets
Monday, 28 August 1995 ·
hard
Rubin C.6-1 6-3
Sukova H.
Rubin C.
662
Sukova H.
130
Chanda Rubin defeated Helena Sukova 6-1 6-3 in the US Open round of 64 on hard. The result followed the form book — Chanda Rubin came in defending last year's round of 128. Chanda Rubin extended the head-to-head to 2–1.
Key context
- Match story: Chanda Rubin dropped just 4 games past Helena Sukova.
Head to head
1–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1997-08-18 | Atlanta | R32 | hard | Chanda Rubin | 6-1 6-2 |
| 1997-07-28 | San Diego | R32 | hard | Helena Sukova | 7-5 3-0 |
Statistics
This season1st serve in·
62%
—
1st serve points won·
60%
—
2nd serve points won·
48%
—
Service points won·
55%
—
Return points won·
46%
—
Break points saved·
52%
—
Aces / match·
1.5
—
Double faults / match·
2.6
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.
Conditions
Court speed
Medium-fastrewards aggression
SlowFast