Renzo Furlan vs David Wheaton — Indianapolis Round of 64
Indianapolis · ATP · Round of 64
2 — 0
Sets
Monday, 14 August 1995 ·
hard
Furlan R.7-6 6-4
Wheaton D.
Furlan R.
7862
Wheaton D.
6640
Renzo Furlan defeated David Wheaton 7-6 6-4 in the Indianapolis round of 64 on hard. The upset overturned the form book — David Wheaton came in leading the head-to-head 1–0, defending last year's round of 32. Renzo Furlan claimed a first win over David Wheaton in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Renzo Furlan edged David Wheaton in two tight sets (7–6 6–4).
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1995-01-16 | Australian Open | R32 | hard | David Wheaton | 7-6(6) 6-4 6-3 |
Statistics
This season1st serve in·Slight edge
55%
60%
1st serve points won·Even
70%
71%
2nd serve points won·Even
49%
47%
Service points won·Even
60%
61%
Return points won·Even
36%
37%
Break points saved·Even
59%
63%
Aces / match·Slight edge
4.7
6.1
Double faults / match·Dominant
2.7
5.0
Averages over each player's completed matches in the selected window (79 vs 39). ATP, WTA & Challenger.