David Wheaton vs Sandon Stolle — Australian Open Round of 128
Australian Open · ATP · Round of 128
3 — 1
Sets
Monday, 18 January 1993 ·
hard
Wheaton D.7-6 6-3 2-6 6-2
Stolle S.
Wheaton D.
776263
Stolle S.
653621
David Wheaton defeated Sandon Stolle 7-6 6-3 2-6 6-2 in the Australian Open round of 128 on hard. The result followed the form book — David Wheaton came in leading the head-to-head 1–0, defending last year's round of 16. David Wheaton extended the head-to-head to 2–0.
Key context
- Match story: David Wheaton closed it out in four sets, 7–6 6–3 2–6 6–2.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1992-02-10 | Memphis | R32 | hard | David Wheaton | 7-6(7) 6-3 |
Statistics
This season1st serve in·Even
60%
60%
1st serve points won·Even
71%
75%
2nd serve points won·Even
47%
46%
Service points won·Even
61%
63%
Return points won·Even
37%
37%
Break points saved·Even
63%
59%
Aces / match·Clear edge
6.1
8.1
Double faults / match·Slight edge
5.0
4.6
Averages over each player's completed matches in the selected window (39 vs 65). ATP, WTA & Challenger.
Conditions
Court speed
Fastbig serves, short points
SlowFast