Pete Sampras vs David Wheaton — US Open Round of 16
US Open · ATP · Round of 16
3 — 1
Sets
Monday, 26 August 1991 ·
hard
Sampras P.3-6 6-2 6-2 6-4
Wheaton D.
Sampras P.
36663
Wheaton D.
62241
Pete Sampras defeated David Wheaton 3-6 6-2 6-2 6-4 in the US Open round of 16 on hard. The result followed the form book — Pete Sampras came in leading the head-to-head 3–0, defending the title. Pete Sampras extended the head-to-head to 4–0.
Key context
- Match story: Pete Sampras dropped the opening set before beating David Wheaton 3–6 6–2 6–2 6–4.
Head to head
3–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1993-11-08 | Antwerp | R32 | hard | Pete Sampras | 6-3 6-2 |
| 1993-04-12 | Hong Kong | QF | hard | Pete Sampras | 6-4 6-4 |
| 1990-10-22 | Stockholm | QF | hard | Pete Sampras | 7-6 5-7 6-4 |
Statistics
This season1st serve in·Even
60%
60%
1st serve points won·Slight edge
80%
71%
2nd serve points won·Slight edge
53%
47%
Service points won·Slight edge
69%
61%
Return points won·Even
36%
37%
Break points saved·Slight edge
69%
63%
Aces / match·Dominant
12.3
6.1
Double faults / match·Even
5.2
5.0
Averages over each player's completed matches in the selected window (200 vs 39). ATP, WTA & Challenger.
Conditions
Court speed
Medium-fastrewards aggression
SlowFast