Robbie Weiss vs Byron Black — Indianapolis Round of 64
Indianapolis · ATP · Round of 64
USARobbie Weiss
Last 10 · pre-match
WLWWWLWWLW
2 — 0
Sets
Monday, 12 August 1991 ·
hard
Weiss R.6-3 6-0
Black B.
Weiss R.
662
Black B.
300
Robbie Weiss defeated Byron Black 6-3 6-0 in the Indianapolis round of 64 on hard. The upset overturned the form book — Byron Black came in leading the head-to-head 1–0, but Robbie Weiss had been the form player, winning 3 of their last 4 on hard. Robbie Weiss claimed a first win over Byron Black in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Robbie Weiss handed Byron Black a second-set bagel in a 6–3 6–0 win.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1993-06-21 | Wimbledon | R128 | grass | Byron Black | 6-2 6-7(7) 6-1 6-1 |
Statistics
This seasonWeiss R.Black B.
1st serve in·
—
61%
1st serve points won·
—
68%
2nd serve points won·
—
51%
Service points won·
—
62%
Return points won·
—
40%
Break points saved·
—
60%
Aces / match·
—
3.8
Double faults / match·
—
2.3
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.