Alejandro Davidovich Fokina vs Botic Van De Zandschulp: Head-to-Head Record
Alejandro Davidovich Fokina and Botic Van De Zandschulp have met 5 times on the professional tour. Alejandro Davidovich Fokina leads the head-to-head 4–1. Their most recent meeting came at Wimbledon in 2025.
Alejandro Davidovich Fokina vs Botic Van De Zandschulp stats comparison
Ratings
Form
Clutch
Under pressurePerformance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About
Freshness
Recent loadAlejandro Davidovich Fokina: 8 days rest · 4 matches (14d) · Botic Van De Zandschulp: 12 days rest · 2 matches (14d). Higher means fresher. About
Serve vs return
Recent formEach player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Set records · last ~30 matches
Career
Profile
Set records use each player's last ~30 completed matches; form shows the last 10 results. Ratings come from the same data that powers the Umpiry Score.
All 5 meetings
- Wimbledon · Round of 642025 · Alejandro Davidovich Fokina won6-1 4-6 6-3 7-6(5)
- Wimbledon · Round of 642023 · Alejandro Davidovich Fokina won6-1 2-6 6-4 6-3
- Hamburg · Round of 322022 · Alejandro Davidovich Fokina won6-4 6-4
- Queen's Club · Quarter-final2022 · Botic Van De Zandschulp won6-2 6-4
- Roland Garros · Round of 642021 · Alejandro Davidovich Fokina won6-4 6-4 5-7 2-6 6-4
Frequently asked questions
Who leads the head-to-head between Alejandro Davidovich Fokina and Botic Van De Zandschulp?
Alejandro Davidovich Fokina leads the head-to-head against Botic Van De Zandschulp 4–1 after 5 meetings.
How many times have Alejandro Davidovich Fokina and Botic Van De Zandschulp played each other?
Alejandro Davidovich Fokina and Botic Van De Zandschulp have played each other 5 times on the professional tour.
When did Alejandro Davidovich Fokina and Botic Van De Zandschulp last play each other?
Their most recent meeting came at Wimbledon in 2025, where Alejandro Davidovich Fokina won.