Aiko Nakamura vs Flavia Pennetta: Head-to-Head Record

Aiko Nakamura

Japan

3–0
3 meetings
Flavia Pennetta

Italy

Hard: 3–0
Aiko Nakamura
3–0
Flavia Pennetta

Aiko Nakamura and Flavia Pennetta have met 3 times on the professional tour. Aiko Nakamura leads the head-to-head 3–0. Their most recent meeting came at Hobart in 2007.

Aiko Nakamura vs Flavia Pennetta stats comparison

Form

WLWWLLLWLWLast 10LLWLWLLWWW
02026 titles0

Clutch

Under pressure
Aiko NakamuraFlavia Pennetta
Clutch Rating·Dominant
43
78
Break points saved·Dominant
34
64
Break points won·Dominant
62
96
Deciding sets·Clear edge
57
74
Tiebreaks·
—
79

Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About

Serve vs return

Recent form
Aiko Nakamuraserving43% hold

wins 47% of points on serve vs Flavia Pennetta

Flavia Pennettaserving69% hold

wins 58% of points on serve vs Aiko Nakamura

Baseline battle — serve is shaky, expect plenty of breaks

Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About

Set records · last ~30 matches

First sets won·Clear edge
43%
57%
Deciding sets won·Slight edge
53%
64%
Tiebreaks won·
33%
—

Career

Career win rate·Clear edge
40%
61%
0Career titles11
0Grand Slam titles1

Profile

42Age44
163 cmHeight172 cm
RightPlaysRight

Set records use each player's last ~30 completed matches; form shows the last 10 results. Ratings come from the same data that powers the Umpiry Score.

All 3 meetings

Frequently asked questions

Who leads the head-to-head between Aiko Nakamura and Flavia Pennetta?

Aiko Nakamura leads the head-to-head against Flavia Pennetta 3–0 after 3 meetings.

How many times have Aiko Nakamura and Flavia Pennetta played each other?

Aiko Nakamura and Flavia Pennetta have played each other 3 times on the professional tour.

When did Aiko Nakamura and Flavia Pennetta last play each other?

Their most recent meeting came at Hobart in 2007, where Aiko Nakamura won.